calculate the total no of atoms present in 224ml of CH4 at S.T.P
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224 ml = .224 l
since 22.4 lit contain 1.602*(10)^²³
hence .224lit contain( 1.602*(10)²³/22.4)*.224
=1.602*(10)²¹ atoms
since 22.4 lit contain 1.602*(10)^²³
hence .224lit contain( 1.602*(10)²³/22.4)*.224
=1.602*(10)²¹ atoms
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