Question

Calculate the total no. of atoms present in a unit cell if 8 atoms are present at 8 corners of the cube and 2 atoms at the centre of each diagonal​

Answer 1

Explanation:

There are four body diagonals and atoms on the body diagonal are not shared by any other unit cell.

∴ Atoms at the corner=8×

8

1

= 1

Atoms on the body diagonal=2×4=8

∴ Total number of atoms =1+8= 9

Answer 2

Answer:

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Explanation:

Calculate the total no. of atoms present in a unit cell if 8 atoms are present at 8 corners of the cube and 2 atoms at the centre of each diagonal