calculate the total no of electron present in 1 moleof CH4
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in one mole of any molecule or atom the no of electrons present = no of electrons present in 1 molecule X Avogadro's no
no of e in ch4 atom = 8
no of e in one mole of ch4 = 8 X 6.023x 10^23
= 48.184 x 10^23 electron
no of e in ch4 atom = 8
no of e in one mole of ch4 = 8 X 6.023x 10^23
= 48.184 x 10^23 electron
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