Question

Calculate the total no. of electrons flowing through a circuit in 20 mins and 40s, if a current of 40 µA flows through the circuit (1 electron = 1.6 X10-19C)​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

The total no. of electrons flowing through a circuit in 20 mins and 40s, if a current of 40 µA flows through the circuit is  $3.1\times 10^{17}$ electrons

Step-by-step explanation:

• Let I be the current flowing, Q be the total charge of electrons and t be the time.

       Then, we have the expression,

       $I=\frac{Q}{t}$  

       Or

       $Q = It$            ...(1)

       Here Q is given by the expression,

       $Q = ne$  

       Or

       $n= \frac{Q}{e}$             ...(2)

       Where e is the charge of one electron and n is the number of electrons.

• In the question, it is given that,

       $t = 20min\ 40 s= (20\times 60)+40= 1240s$

      $I = 40\mu A = 40\times 10^{-6} A$  

       $e = 1.6\times 10^{-19}C$

      Substitute these values into equation (1)

      $Q = (40\times 10^{-6 }) \times 1240 = 0.0496 C$

      Then equation(2) becomes,

      $n= \frac{0.0496}{1.6\times 10^-19}= 3.1\times 10^{17}$ electrons