Question

calculate the total no.of electrons present in 1.4 g of N2 gas

Answer 1

Number of moles in the given weight of Nitrogen gas.
Number of moles = Given weight/molecular weight
= 1.4/28
=0.05 moles
1 mole of Nitrogen contains Avogadro number (6.023*1023) of Nitrogen molecules.
0.05 moles of Nitrogen contains = 0.05*6.023*1023
= 3.011*1022 molecules
1 molecule of Nitrogen contains 14 electrons
3.011*1022 molecules contains = 3.011*1022*14
= 42.154*1022
= 4.215*1023 number of electrons

Answer 2

Hey !
Here is your answer !!
__________________


➡Number of moles = Given weight / Molecular weight

➡Number of moles = 1.4 / 28 = 14 / 280 = 1 / 20 = 0.05 moles


Now !
➡1 mole of nitrogen contains 6.022 × 10^23 molecules of nitrogen


➡0.05 moles will contain ---- 0.05 × 6.022 × 10^ 23 molecules


= 3.011 × 10^22 molecules



Now !

➡1 molecule of Nitrogen contain 14 electrons

➡So 3.011 × 10^22 molecules will contain ---


➡3 × 10^22 × 14 electrons

= 4.21 × 10^23 electrons

Hope it helps !!