Question

Calculate the total no. Of electrons present in 1.4g of dinitrogen gas

Answer 1

Hope this will help u Given mass of dinitrogen=1.4g Molar mass of dinitrogen=28g Moles of dinitrogen=given mass/molar mass =1.4/28 =0.05 No. Of atoms in 0.05 dinitrogen=0.05*avogadro no. =0.05*6.022*10^23 =3.011*10^22 atoms No.of electrons in 1 atom of dinitrogen=14 electrons No. Of electrons in 3.011*10^22 atoms of dinitrogen=3.011*10^22*14 =4.215*10^23 electrons

Answer 2

HÈLLØ!!

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$\Huge{\mathfrak{\blue{\underline{ANSWER}}}}$

Molar mass of dinitrogen (N2) = 28 g mol-1

Thus, 1.4 g of N2

= 1.4/28

= 0.05 mol

= 0.05 × 6.02 × 10²³ no of molecules

= 3.01 × 10²³ no. of molecules

Now, 1 molecule of N2 has 14 electrons.

Therefore, 3.01 × 10²³ molecules of N2 contains,

= 14 × 3.01 × 10²³

= 4.214 × 10²³ electrons.

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THÅÑKẞ!!