Question

Calculate the total no. of electrons present in 1.6 g of methane??​

Answer 1

Here is ur answer:

1 mole of methane weighs 16.04 g. 1.6 g of methane, therefore is roughly 0.1 mole. A mole of any substance contains 6.023 X 10^23 molecules. ... Hence total number of electrons = number of electrons present in CH4 × atoms present in 0.1 mole.

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Answer 2

Q. Calculate the total no. of electrons present in 1.6 g of methane. ✒

$ans = 6.022 \times {10}^{23}$

Explanation:-

Molecular Mass of methane(CH4)

$(1 \times 12 + 4 \times 1 \: \: \:) gm$

$16gm$

$16gm \: of \: methane \: contains = 6.022 \times {10}^{23} molecules$

$1.6 \: g \: of \: methane \: contains \: = \frac{6.022 \times {10}^{23} \times 1.6 }{16}$

$= 6.022 {10}^{22} molecules$

One molecule of CH4 contains =6 + 4 = 10 electrons

$no.of \: electrons \: in \: 1.6 \: gm \: of \: methane \: = 6.022 \times {10}^{22} \times 10$

$= 6.022 \times {10}^{23} electrons$