Question

Calculate the total no. of electrons present in 35.5gm of chloride ions​

Answer 1

Answer:

Since 35.5g is one mole of chlorine, we have  6.022 × 1023  molecules of the gas.

Since chlorine gas is diatomic (Cl2), there are 2×6.022 × 1023=1.204×1024  atoms of chlorine in the 1 mole.

Answer 2

Answer:

I think 0.01 NA

Explanation:

Clc- + e- =1/2Cl2

If =1e- = 1 molofe- = NA= 35.5g Cl2

therefore 35.5g of Cl2=NA*0.355 divided by 35.5

=0.01NA