Calculate the total no. of oxygen and nitrogen atoms present in a mixture containing 8.2 gm of calcium 10 millimoles of sodium nitrate and NA/6 molecules of NO2.
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The mass of 1 mole of a gas is equal to its molecular weight.
Thus 8 grams of oxygen correspond to
32
8
=0.25 moles of oxygen.
At STP, 1 mole of a gas occupies 22.4 L.
Thus 11.2 L of carbon dioxide corresponds to
22.4
11.2
=0.5 moles.
1 mole of gas contains Avogadro number of molecules which is equal to 6.02×10
23
.
Thus 3×10
22
molecules of nitrogen corresponds to
6×10
23
3×10
22
=0.05 moles.
Thus the total number of moles present is 0.25+0.5+0.05=0.80.
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