Calculate the total no. of oxygen atoms in 1.8 g of glucose
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C6H12O6 = 180g
1 mole of glucose = 180g
No. of moles of glucose in 1.8g of glucose = 1.8/180= 1/100
Total no. of Atoms in 1/100 mol=( 1/100)× 6.022×10^23
1mole of glucose contain 6mole of oxygen
Total no. of oxygen in one mole of Glucose is = (1/100)×6.022×10^23 × 6 = 3.61× 10^22
1 mole of glucose = 180g
No. of moles of glucose in 1.8g of glucose = 1.8/180= 1/100
Total no. of Atoms in 1/100 mol=( 1/100)× 6.022×10^23
1mole of glucose contain 6mole of oxygen
Total no. of oxygen in one mole of Glucose is = (1/100)×6.022×10^23 × 6 = 3.61× 10^22
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