Question

Calculate the total no of protons present in 112g of n2

Answer 1

Molecular mass of n2 = 28u

Number of moles = 112/28

= 4 moles

No of molecules = 4 × 6.022×10^23

= 24.088 × 10^23

One molecule of n2 contains 14 protons

So total no of protons = 14 × 24.088 × 10^23

= 337.2 32 × 10^22

= 3.372 × 10^25