Question

Calculate the total no. of vol.
present in a drop of water which
weight 0.9 gram.​

Answer 1

Answer:

Dude... Is this in 10th grade portions???

Answer 2

Given, mass of H2O = 0.9g

=> no. of moles of H2O = 0.9g/ 18g = 0.05 mol H2O

Since, 1 mole of H2O = 22.7L
=> 1 = 22.7L / 1 mol

.°. 0.05 mole of H2O = 0.05 mol × (22.7L / 1 mol) = 1.135L = 1.14L

Hence, the total volume present in a drop of water is 1.14L .





HOPE IT'LL HELP...