Chemistry, asked by haripriyasuthar7, 6 months ago

calculate the total node angular nodes and radial node
in the following orbital
Radial 6f ,4 d , 2d ,5s, 3f, 3 p​

Answers

Answered by kundanconcepts800
1

Answer:

6f

total nodes 5

angular nodes= 3

radial nodes = 2

4d

total nodes = 3

angular nodes = 2

radial nodes= 1

2d -orbital not possible

5s

total nodes= 4

radial nodes= 4

angular nodes = 0

3f not possible

3p - orbital

total nodes = 2

radial nodes= 1

angular nodes= 1

Explanation:

total no.of nodes =n-1

angular nodes = l

radial nodes = n-l-1

Similar questions