Question

Calculate the total number of atoms, electrons, protons, neutrons in 360 g of C6H12O6​

Answer 1

Mass of one mole of glucose $\sf C_6H_{12}O_6$ is 180g.

In one mole of glucose, there are 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms.

Now,

No.of electrons = No.of protons = 6 × 6 + 12 × 1 + 6 × 8 = 96

No.of neutrons = 6 × 6 + 12 × 0 (In $\sf _1H^1$ no of neutrons is zero) + 6 × 8 = 84

In 360g of glucose which is 2 moles of glucose $\sf 2C_6H_{12}O_6$,there will be double the number of atoms (36 atoms), thus double the electrons, protons and neutrons. There will be 192 protons and electrons and 168 neutrons.