calculate the total number of atoms in 0.5 mol of k2cr2o7 . Question number 2
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Answered by
44
Hey there !!
Here’s the solution :
No. Of moles = 0.5; Let the number of atoms be “x”
Formula : No. of moles = No. of atoms of K₂Cr₂O₇/ Avagadro’s constant
0.5 = x/6.022*10²³
x = 6.022*10²³ * 0.5
x = 3.011 *10²³
Therefore, the number of K₂Cr₂O₇ is 3.011 *10²³
Hope this helps ya ✌️✌️
Here’s the solution :
No. Of moles = 0.5; Let the number of atoms be “x”
Formula : No. of moles = No. of atoms of K₂Cr₂O₇/ Avagadro’s constant
0.5 = x/6.022*10²³
x = 6.022*10²³ * 0.5
x = 3.011 *10²³
Therefore, the number of K₂Cr₂O₇ is 3.011 *10²³
Hope this helps ya ✌️✌️
parnex:
thanks i did the same like this
Then it’s right.
like this 1 mole = 6.02x10²³ so 0.5 mole = x . then cross multiplied . Is it correct?
Logically yes, but it would be better if you quote the formula
ok ty :)
Anytym
Answered by
4
Answer:3.011×10^23
Explanation:No. Of moles = 0.5; Let the number of atoms be “x”
Formula : No. of moles = No. of atoms of K₂Cr₂O₇/ Avagadro’s constant
0.5 = x/6.022*10²³
x = 6.022*10²³ * 0.5
x = 3.011 *10²³
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