Question

calculate the total number of atoms presenr in 9 grams of water

Answer 1

moles in 9g water = mass/molar mass

= 9/18

= 0.5

no. of atoms = moles × Avagadro no

$no \: of \: atoms = 0.5 \times 6.022 \times {10}^{23}$

$= 3.011 \times {10}^{23}$

Answer 2

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