Question

calculate the total number of atoms present in 18 gram of water​

Answer 1

$\huge❥\red{\underline{{\bf answer:- }}}$

It is equal to Avogadro's number (NA), namely 6.022 x1023. If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams.

Answer 2

Answer:

. Therefore 18gm of watercontains 1mole of water i.e. 18 gm ofwater contains 6.023 × 10²³molecules. Now, 1 molecule of watercontains 2 atoms of hydrogen and 1atom of oxygen i.e. 3 atoms. Therefore 6.023 × 10²³ molecules contain 6.023 × 10²³ × 3 = 1.8069 × 10²⁴ atoms.