Calculate the total number of atoms present in 18g h2o
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there are 6.023 × 10^23 atoms in 18 grams of water
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It is equal to Avogadro's number (NA), namely 6.022 x1023. If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams.
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