Question

Calculate the total number of Cl atoms in 150ml of liquid CCl4 (d=1.589g/ml)

Answer 1

Answer:

Mass of CCl4 = Vol. x density = 150 x 1.589 = 238.35g

    Moles of CCl4 = 238.35/154 = 1.54

Now 1 mol CCl4 contains 4 mol of Cl atoms i.e. 4 x 6.02 x 10^23 Cl atoms

Hence 1.54 mol of CCl4 will contain = 1.54x 4 x 6.02 x 10^23 = 3.11 x 10^24 Cl atoms

Explanation:

Answer 2

Answer:

1.54x 4 x 6.02 x 1023 = 3.11 x 1024.

Explanation:

Vol. x density of CCl4 is 150 x 1.589 = 238.35g.

CCl4 moles equal 238.35/154 = 1.54

Currently, 4 mol of Cl atoms, or 4 × 6.02 x 1023 Cl atoms, are present in 1 mol of CCl4.

Hence The number of Cl atoms in 1.54 mol of CCl4 will be 1.54x 4 x 6.02 x 1023 = 3.11 x 1024.

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