Question

Calculate the total number of electron present in 1.6g of methane.
​

Answer 1

Answer:

6.022×10²² or 6.023×10²³

Explanation:

Formula of methane = CH4

Gram molecular weight of methane = C+4×H= 12+4×1= 16gm

16 gm of methane = 1 mole

1 gm = 1/16 mole

1.6 gm = 1/16 × 1.6 = 0.1 mole

1 mole = 6.023×10²³ ions or 6.022×10²³

0.1 mole = 6.023×10²³ × 0.1 = 6.023×10²² or 6.022×10²² electrons.

Answer 2

$\huge {\blue {\boxed {\green {\boxed {\red {\boxed {\bf {\mathfrak {\pink {A}\purple {N}\orange {S}\blue {W}\red {E}\green {R:}}}}}}}}}}$

0.1 moles of methane (1.6g) contains '0.1×Avogadro number' molecules.

THUS,

0.1 mole of ${CH}{4}$ contains "10×0.1×Avogadro number" of electrons.

THEREFORE,

1.6g of methane contains 6.022×${10}^{23}$ electrons.