Question

calculate the total number of electrons in 3.2 gram of sulphur​

Answer 1

Answer:

Explanation:

Given:

3.2g of sulphur

To find:

Number of atoms in 3.2g of sulphur = ?

Calculation:

1 mole of substance contains = 6.022 * 10²³

32g of sulfur = 6.022 * 10²³ atoms.

1 g of sulfur = 6.022 * 10²³ / 32 atoms.

3.2 g of sulfur = 6.022 * 10²³ * 3.2 / 32 atoms.

3.2 g of sulfur = 6.022 * 10²²

Conclusion:

3.2g of sulfur contains  6.022 * 10²²  atoms.

Answer 2

Answer:

꧁꧂Hey mate ur answer is

Molar mass of O2 = 32g

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.2

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 mol

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×1023

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×1023No of electrons in one molecule of O2 = 8

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×1023No of electrons in one molecule of O2 = 8×

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×1023No of electrons in one molecule of O2 = 8×2=16

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×1023No of electrons in one molecule of O2 = 8×2=16No of electrons in 0.1

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×1023No of electrons in one molecule of O2 = 8×2=16No of electrons in 0.1×

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×1023No of electrons in one molecule of O2 = 8×2=16No of electrons in 0.1×6.022

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×1023No of electrons in one molecule of O2 = 8×2=16No of electrons in 0.1×6.022×

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×1023No of electrons in one molecule of O2 = 8×2=16No of electrons in 0.1×6.022×1023 molecules = 0.1

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×1023No of electrons in one molecule of O2 = 8×2=16No of electrons in 0.1×6.022×1023 molecules = 0.1×6.022×1023

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×1023No of electrons in one molecule of O2 = 8×2=16No of electrons in 0.1×6.022×1023 molecules = 0.1×6.022×1023×

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×1023No of electrons in one molecule of O2 = 8×2=16No of electrons in 0.1×6.022×1023 molecules = 0.1×6.022×1023×16 = 9.6352

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×1023No of electrons in one molecule of O2 = 8×2=16No of electrons in 0.1×6.022×1023 molecules = 0.1×6.022×1023×16 = 9.6352×

Molar mass of O2 = 32gNo of moles in 3.2 g O2 =3.232= 0.1 molNo of oxygen molecules = 0.1×6.022×1023No of electrons in one molecule of O2 = 8×2=16No of electrons in 0.1×6.022×1023 molecules = 0.1×6.022×1023×16 = 9.6352×1023 electrons