Question

Calculate the total number of electrons present in 1.4 g of dinitrogen gas.​

Answer 1

Answer:

4.214 × 1023 electrons

Explanation:

Molar mass of dinitrogen (N2) = 28 g mol-1

Thus, 1.4 g of N2

= \frac{ 1.4 }{ 28 }

28

1.4

= 0.05 mol

= 0.05 × 6.02 × 1023 no of molecules

= 3.01 × 1023 no. of molecules

Now, 1 molecule of N2 has 14 electrons.

Therefore, 3.01 × 1023 molecules of N2 contains,

= 14 × 3.01 × 1023

= 4.214 × 1023 electrons

Hope it is helpful