Question

Calculate the total number of electrons present in 1.48
nitrogen gas?​

Answer 1

Answer:

1 mole of any molecule has 6.022 x 1022 molecules, 0.05 moles of N2 = 0.05 x 6.022 x 1022 molecules. 1 molecule of nitrogen has 14 electrons in it. HÈLLØ!!

Answer 2

Answer:

4.21 × 10²³ electrons.

Explanation:

We have :

Given mass = 1.4 g

We know :

No. of moles = Given mass / Molar mass

Molar mass of Nitrogen gas N₂ = 24 g / mol

No. of moles = 1.4 / 28 mol

No. of moles = 0.05 mol

Now :

No. of molecules of N₂ gas = 0.05 × 6.02 × 10²³ molecules

= > No. of molecules of N₂ gas = 3.01 × 10²² molecules

Total number of electrons present in 1.48  nitrogen gas :

= > 14 × 3.01 × 10²² electrons

= > 4.21 × 10²³ electrons.

Therefore , we get required answer.