Question

Calculate the total number of electrons present in 1.4g of dinitrogen gas

Answer 1

Hi there,

Ans:

Number of moles in the given weight of Nitrogen gas.
Number of moles = Given weight/molecular weight
= 1.4/28
=0.05 moles
1 mole of Nitrogen contains Avogadro number (6.023*1023) of Nitrogen molecules.

0.05 moles of Nitrogen contains = 0.05*6.023*1023
= 3.011*1022 molecules

1 molecule of Nitrogen contains 14 electrons
3.011*1022 molecules contains = 3.011*1022*14

= 42.154*1022

= 4.215*1023 number of electrons

Answer 2

HLO MATE HERE U GO

⭐. No .of Moles of N2 = 1.4/ 28= 0.05 .

Avahadroś number N = 6.023× 10^23

No .of electrons in N2 molecule = 2× 7= 14 .

Total No .of electrons

= No .of moles × Avagadros number × No . of electrons in N2

= 0.05 × 6.023 × 10^23 × 14 = 4.216×10^23.