calculate the total number of electrons present in 1.4g of n2 gas
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Molar mass of N2 = 28 g mol–1
Thus, 1.4 g of N2 = 1.4/28
= 0.05 mol
= 0.05 x 6.023 x 10^23
= 3.01 x 10^23
1 molecule of N2 contains 14 electrons.
Hence, 3.01 × 10^23 molecules of N2 contains
= 14 × 3.01 × 10^23
= 4.214 × 10^23 electrons
Thus, 1.4 g of N2 = 1.4/28
= 0.05 mol
= 0.05 x 6.023 x 10^23
= 3.01 x 10^23
1 molecule of N2 contains 14 electrons.
Hence, 3.01 × 10^23 molecules of N2 contains
= 14 × 3.01 × 10^23
= 4.214 × 10^23 electrons
devenderbisht7pcmy4j:
are you lived in delhi
because i love chemistry..... it type of in my class...
no i am from meerut ( uttar pradesh )
ohh
can we become friends
are you crazy
you are wrong 10^23 electrons
no sorry you are right
srry my mistake
ok
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