Question

Calculate the total number of electrons present in 1.6 g of methane

Answer 1

first we have to find mole.
1.6/16=0.1
now we multiply it Avogadro's no.
to get no. of moles
0.1*6.023*10^23
now we multiply it by total no. of electrons
6.023*10^22*(6+4)=6.023*10^23

Answer 2

MW of methane = 16 g/mole So, no of moles of methane in 1.6 g = 1.6 /16 g/mole = 0.1Since, in 1 mole methane there are 6.022 x 1023 molecules of methane,  so, in 0.1 mole there will be 0.1 x 6.022 x 1023 molecules of methane In 1 methane molecule there are 10 electrons (6 + 4) total electrons in 0.1 mole or 1.6 g = 10 x 0.1 x 6.022 x 1023 = 6.022 x 1023