Question

Calculate the total number of electrons present in 18 ml of water

Answer 1

no. of moles of water
$\frac{18g}{18g} = 1mol$
no. of electrons in one water molecule
$1 \times 2 \: hydrogen \: electrons \: +$
$8 \times 1 \: oxygen \: electrons$

=10 electrons.

So no of electrons in 1 mol
= 10 x (6.022x10^23)
= 6.022 x 10^24 electrons.

Answer 2

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