Calculate the total number of electrons present in 18ml of water
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HI FRD HERE UR ANS ...
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✔ But each molecule of water contains 10 electrons. Thus 6.023 x 10^(23) molecules of water will contain 10 x 6.023 x 10^(23) electrons= 6.023 x 10^(24) electrons.
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✔ 18 ml of water is equal to 18 g of H20.
i hope help u jii
HI FRD HERE UR ANS ...
....⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️
✔ But each molecule of water contains 10 electrons. Thus 6.023 x 10^(23) molecules of water will contain 10 x 6.023 x 10^(23) electrons= 6.023 x 10^(24) electrons.
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✔ 18 ml of water is equal to 18 g of H20.
i hope help u jii
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Hey mate ^_^
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Answer:
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Here we will use the the concept of density of water = 1g/cc
D=M/V
1 g/ml = M/18 ml
M= 18 g
Moles of water = mass/molar mass = 18/18 = 1
1 mole of water contains = NA molecules
Total electrons in water = 2(H) + 8(O) = 10
1 molecule of water contains = 10 electrons
1 mole water contains = 10 * NA electrons
NA = Avogadro’s number
#Be Brainly❤️
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Answer:
=======
Here we will use the the concept of density of water = 1g/cc
D=M/V
1 g/ml = M/18 ml
M= 18 g
Moles of water = mass/molar mass = 18/18 = 1
1 mole of water contains = NA molecules
Total electrons in water = 2(H) + 8(O) = 10
1 molecule of water contains = 10 electrons
1 mole water contains = 10 * NA electrons
NA = Avogadro’s number
#Be Brainly❤️
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