calculate the total number of electrons present in one mole of mathane
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CH4= 1 *6+4*1=10electrons....
And one mole of methane contains 6.022*10^23 molecule hence no. Of electron =10*6.022*10^23=6.022*10^24
And one mole of methane contains 6.022*10^23 molecule hence no. Of electron =10*6.022*10^23=6.022*10^24
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