Question

Calculate the total number of electrons, Protons present in
9.8 g of Sulphur dioxide. ​

Answer 1

Answer:

Correct answer is

0.6023×10 ^23

∵98 gH

2

SO

4

contains1 mole of H

2

SO

4

.

1 mole of H

2

SO

4

contain=1 mole of sulphur atoms.

∴9.8 g of H

2

SO

4

contain =0.1 mol of sulphur atom.

Thus, number of sulphur-atoms =n×N

A

(in 9.8 g of H

2

SO

4

)

=0.1×6.023×10 ^23

=0.6023×10 ^23

.