Question

calculate the total number of ions in one gram of Na2HPO4 (mass number ofNa23 H 1.008 p31 o16

Answer 1

Answer:

ions of Na2HPO4 =(Na)2 ^+ and (HPO4)

2Na^+1 and 1(HPO4)^2

total ions=3

1 gram Na2HPO4 = 1/142 moles

1 mole=ions*NA

1=3*NA

in 1/142 moles

=3*NA/142

=3*6.023*10^23/142

=18.069*10^23/142

=0.2724*10^23 ions