Question

calculate the total number of ions in one gram of na2hpo4​

Answer 1

total no of ions are 8

Answer 2

Answer: The total number of ions in given amount of ionic compound is $0.127\times 10^{23}$

Explanation:

To calculate the molecular mass of solute, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Mass of sodium hydrogen phosphate = 1 g

Molar mass of sodium hydrogen phosphate = 142 g/mol

Putting values in above equation, we get:

$\text{Moles of }Na_2HPO_4=\frac{1g}{142g/mol}=0.00704mol$

According to mole concept:

1 mole of an ionic compound contains $6.022\times 10^{23}$ number of ions.

The chemical equation for the ionization of sodium hydrogen phosphate follows:

$Na_2HPO_4\rightarrow 2Na^++HPO_4^{2-}$

1 mole of sodium hydrogen phosphate produces $(3\times 6.022\times 10^{23}$ number of ions.

So, 0.00704 moles of sodium phosphate will produce = $0.00704\times 3\times 6.022\times 10^{23}=0.127\times 10^{23}$ number of ions.

Hence, the total number of ions in given amount of ionic compound is $0.127\times 10^{23}$