Calculate the total number of oxygen atoms present in 1.80 gram of glucose c6 h12 o6
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moles = 1.80/96
=0.01875
total o atoms : 6
therefore oxygen atoms is 0.01875×6×6.022×10²³
=0.01875
total o atoms : 6
therefore oxygen atoms is 0.01875×6×6.022×10²³
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