Calculate the total number of oxygen molecules present in 18 gram of glucose
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Glucose⟶C 6 H 12 O 6
Number of moles= molecular mass/mass
=180/1.8
=0.01 mol
Now, there are 6 atoms of oxygen
Total number of oxygen atoms=number of atoms of oxygen×number of moles×Avagadro's constant
=6×0.01×6.023×1023
=36.138×1021
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