calculate the total of number election present in 1.6g of methane
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Answer:
The total no. of electrons in one mole of any compound is equal to Avogadro's no.
Explanation:
The molecular mass of methane ch4 is 16g (12+4*1)
Hence 1.6g will contain 0.1 mole
Hence it will be 0.1 Avogadro no.=6.022*10^21
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