Question

calculate the total of the relaxation of 2 moles of an ideal gas from an initial pressure of 4.0 into 10 power 5 Newton metre to find pressure of 2.7 to 10 days 15 metre metre at 298 Kelvin​

Answer 1

Answer:

plz mark as brainliset or put 5 strs plz plz

Explanation:

Mass of urea = 5 g

Mass of water = (100-5)= 95 g

No. of moles of area     = 5/60

                                      = 0.083

No. of moles of water   = 95/18

                                      = 5.278

Total number of moles = 5.278+0.083

                                      = 5.361  

Mole fraction of solvent = 5.278/5.361

Ps=Mole fraction of solvent x P0

​   = 5.278/5.361 X 23.5 =23.14 mm