Question

Calculate the total percentage of oxygen in copper sulphate crystals: CuSO4.5H2O (Cu=64, S=32,O=16,H=1) *

Answer 1

Answer:144/250*100= 57.6%

Percentage of oxygen is 57.6%

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Explanation:

Answer 2

Answer:

57.6%

Explanation:

TOTAL MASS OF CUSO4.5H2O = 250g

% of O in CUSO4.5H2O =

$9 \times 16 \div 250 \times 100$

$= 0.576 \times 100$

$= 57.6$

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