Calculate the total pressure exerted by 8 gram of oxygen and 8 gram of hydrogen in vessel of 2 cm 3 at 27 degrees
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Answered by
15
Answer:
no. of moles of oxygen = 8 / 32 = 0.25
No. of moles of nitrogen = 14 / 28 = 0.5
Volume of the container = 11.2 Litre
temperature = 0°c or 0+ 273 = 273 K
assuming ideal gas behaviour
P = n RT / V
= 0.75 × 0.0821 ×273 /11.2
= 1.501 atm
Answered by
0
Answer:
no. of moles of oxygen = 8 / 32 = 0.25
No. of moles of nitrogen = 14 / 28 = 0.5
Volume of the container = 11.2 Litre
temperature = 0°c or 0+ 273 = 273 K
assuming ideal gas behaviour
P = n RT / V
= 0.75 × 0.0821 ×273 /11.2
= 1.501 atm
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