Question

Calculate the total pressure in a mixture of 16g of oxygen and 20 g of hydrogen
confined in a vessel of l dm3 at 37 °C. R = 0.083 bar dm3 K-1 mol-1


pls dont give wrong answer
.

Answer 1

Answer:

Mass of oxygen = 8 g, molar mass of oxygen = 32 g/mol

Mass of hydrogen = 4 g, molar mass of hydrogen = 2 g/mol

Therefore amount of oxygen = 8/ 32 = 0.25 mol

And amount of hydrogen = 4/2 = 2 mol

From the gas equation PV = n RT, we get,

P X 1 = (0.25 + 2) X 0.083 X 300 = 56.02 bar

Hence, the total pressure of the mixture is 56.02 bar.