Question

Calculate the total quantity (cubic meter) of the coarse aggregate required for an isolated rectangular footing of size 3 m x 2 m, if 1 : 2 : 4 cement concrete is used. The depth of the footing is 600 mm.

Answer 1

volume of coarse needed 3x2x0.6=3.6 cu.m

Answer 2

Answer:

$1.8m^3$

Step-by-step explanation:

Cement : Sand : Coarse = 1:2:3

Total Part of the Concrete = 1+2+3 =6 parts

Length of rectangular footing = 3 m

Breadth of rectangular footing = 2 m

The depth of the footing = 600 mm = 0.6 m

Volume  = $Length \times Breadth \times Depth$

Volume  = $3 \times 2 \times 0.6$

Volume  = $3.6m^3$

Coarse Aggregate = (Coarse Aggregate Part / Concrete Parts ) * Concrete Volume

Coarse Aggregate = $\frac{3}{6} \times 3.6$

Coarse Aggregate = $1.8m^3$

Hence  the total quantity (cubic meter) of the coarse aggregate required for an isolated rectangular footing is  $1.8m^3$