Question

Calculate the total resistance between point A and B as shown on the figure given bellow​

Answer 1

Answer:

5+2+3+3+6=19

Explanation:

I think the answer is 19

Answer 2

$\huge \purple {Answer}$

As, 5Ω and 2Ω are in parallel
Therefore, resistance of both will be:-
$\frac{1}{5} + \frac{1}{2}$Ω

$\frac{2 + 5}{10}$Ω

$\frac{7}{10}$Ω

Similarly, 3Ω and 3Ω are in parallel
Therefore, resistance of both will be:-
$\frac{1}{3} + \frac{1}{3}$Ω

$\frac{1 + 1}{3}$Ω

$\frac{2}{3}$Ω

Now add all

$\frac{7}{10}$ + $\frac{2}{3}$ + 6Ω

$\frac{21 + 20 + 180}{30}$Ω

$\frac{221}{30}$Ω

Therefore, there is $\frac{221}{30}$Ω total resistance in the circuit.