Question

Calculate the total stopping distance for an initial velocity of 72 km/h and assume acceleration of car is – 4.0 m/s2 (the minus sign appears because the velocity is taken as
positive along x- axis and its magnitude is decreasing). Reaction time for normal drivers
varies from perhaps 0.3 s to about 1.0 s; take it be 0.50 s for this problem calculation.​

Answer 1

Answer:

Explanation:

Pressure at A=fuly×g×20100

PA=1300×10×20100

PA=2600N/M2

Pressure at B =foil×g×h+fHh×g×(20−h)100

PB=800×10×h100+13.6×103×10×(20−h)100

PB=80h+1360(20−h)

As PA=PB,

⇒2600=80h+27200−1360h

⇒1280h=27200−2600

⇒1280h=24600

⇒h=246001280=1921875

h=19.22cm

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Answer 2

Answer:

The answer to the given question is 9.5 meters.

Explanation:

Given,

In the given question information is given about a car moving with some initial velocity and acceleration. We need to find the stopping distance of the car.

The initial velocity of the car is 72km/hr

The acceleration of the car is $-4m/s^{2}$  {the minus sign appears because the velocity is taken as positive along the x-axis and its magnitude is decreasing}

Time=0.5 seconds

Initial velocity, u= 72km/hr

u= 72×$\frac{5}{18}$=20m/s

a= $-4m/s^{2}$

t=0.5seconds

To find the stopping distance, we can use the second equation of motion,

$s=ut+\frac{1}{2}at^{2}$

s=20×0.5+1/2×(-4)×0.5×0.5

s=10-0.5

s=9.5 meters

The total stopping distance is 9.5 meters.

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