calculate the total surface area of the outside of an open box (without a lid ) which has a base measuring 1.0mby0.8m and has a height of 0.5m
Neetu1976:
please answer
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Answered by
10
Given; b=1 m,l=0.8 m and h=0.5 m
We know that, total surface area of a cuboid= 2(lb+bh+hl)
This implies, the total surface area of the box= 2(lb+bh+hl)-lb
Where, lb is the area of the lid.
So,TSA of the box= 2(bh+hl)+lb
Hence, TSA of the box= 2{(1*0.5)+(0.8*0.5)}+(1*0.8)
=2(0.5+0.4)+0.8
=1.8+0.8=2.6 m²
Hence, the total surface area of the box is 2.6 m²
We know that, total surface area of a cuboid= 2(lb+bh+hl)
This implies, the total surface area of the box= 2(lb+bh+hl)-lb
Where, lb is the area of the lid.
So,TSA of the box= 2(bh+hl)+lb
Hence, TSA of the box= 2{(1*0.5)+(0.8*0.5)}+(1*0.8)
=2(0.5+0.4)+0.8
=1.8+0.8=2.6 m²
Hence, the total surface area of the box is 2.6 m²
Answered by
3
Answer:
2.6 m^2
Step-by-step explanation:
given,
l=0.8, b=1, h=0.5
as we know that,
The Total Surface of Cube or a Cuboid =2(lb+bh+hl)
area =2(1*0.8+0.8*0.5+0.5*1)
=2*1.3
=2.6 m^2
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