Chemistry, asked by mayurtambe611, 4 months ago

calculate the transmittance of a solution which absorb 80% of incident radiation​

Answers

Answered by farhaanaarif84
0

Answer:

Many compounds absorb ultraviolet (UV) or visible (Vis.) light. The diagram below shows a beam of monochromatic radiation of radiant power P0, directed at a sample solution. Absorption takes place and the beam of radiation leaving the sample has radiant power P.

The amount of radiation absorbed may be measured in a number of ways:

Transmittance, T = P / P0

% Transmittance, %T = 100 T

Absorbance,

A = log10 P0 / P

A = log10 1 / T

A = log10 100 / %T

A = 2 - log10 %T

The last equation, A = 2 - log10 %T , is worth remembering because it allows you to easily calculate absorbance from percentage transmittance data.

The relationship between absorbance and transmittance is illustrated in the following diagram:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.

Answered by shruuti25
0

Answer:      

Explanation:

  • Transmittance  refers to how much light passes through a sample unchanged.

The relationship between absorbance and transmittance is given by:

A = log10( 1 / T) or A = -log10 (T)

The last equation makes it easy to calculate the absorbance from the transmittance data.

0.80= - log10 (T)

-0.80= log10 (T)

log(t)/log(10) = -0.8

log(T)/(log(2) + log(5)) = -0.8

T = 0.158489

The transmittance of the solution is therefore 0.158489

Also, if all the light passes through the solution without any absorption, then the absorbance is zero and the percent transmittance is 100%. If all the light is absorbed, then the percent transmittance is zero and the absorption is infinite.

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