Calculate the turnover number (sec-1) for an enzyme, if Km = 0.001 µM; Vmax = 10
µM/sec; and E0= 0.001 µM.
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Answer:
12 .km.oooo.1 2.9.km sec Eo .ooo2.332 kms
Answered by
0
Answer:
12 .km.ooooo.1 2.9.km sec Eo .ooo2.332 km/s
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