Question

calculate the two irrational no. between 2 and 2.5 by step by step

Answer 1

since ,we have :--

2.5&2 as rational numbers

BUT

2=

$\sqrt{4}$

2.5=

$\sqrt{2.5 \times 2.5}$

=

$\sqrt{6.25}$

then the irrational numbers between

$\sqrt{4 \: \leqslant and \:} \: \sqrt{6.25} are$

$\sqrt{5 \: } and \sqrt{6} \: \: answer$