Question

Calculate the uncertainty in position of an electron if the uncertainty in velocity is 5.7x10 m s

Answer 1

Given, uncertainty in velocity
∆v = 5.7×10m/s
Mass of electron = 9.1×10^-31kg.
Therefore , uncertainty in position ∆x = h/4π×m × ∆v...
Where h is the plancks constant 6.626×10^-34Js...


∆x = 6.626×10^-34/4(3.14)9.1×10^-31×5.7×10~ 269.7 × 10^-2...

Therefore, ∆x = 269.7×10^-2



Hope it helps you.