Question

Calculate the uncertainty in the position of an electron if the uncertainty
in its velocity is 5.7 x 10 5 m/s.
(h= 6.6 x 10 -34 Kgm2
s-1
, mass of electron = 9.1 x 10 -31 K

Answer 1

Answer:

ΔV= 5.7×105 m/sec Δx=?

h= 6.6×10–34 Joule-Sec.

Δx.Δv ≥h/4πm

Δx≥h/4πmΔv

≥6.6×10–34/9×3.14×9.1×10–31×5.7×105

≥ 0.010×10–8

≥ 1×10–10m

Explanation:

please do follow me