Question

Calculate the uncertainty in the position of an electron if uncertainty in its velocity is 0.001

Answer 1

from Heisenberg uncertainty principle we have

∆p•∆x is greater than or equal to h cut divided by 2.

for simplicity we take the product to be equal to h cut by 2.

Then,

∆p•∆x=h/4π (since h cut = h by 2π)

(m•∆v)•∆x=h/4π

∆x=h/(4πm•∆v)

$m = 9.1 \times {10}^{ - 31} \\ delta \: v = 0.001 \\ h = {6.626 \times 10}^{ - 34}$

on substituting and calculating we get,

∆x=0.057m(approx)