Calculate the valency of the following element? a) carbon b) fluorine c) calcium d) phosphorous(show the calculation)
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Answer:
a) The outer electronic configuration of carbon is 2s22p2. Thus, it has 4 valence electrons. It shares these 4 valence electrons to form 4 covalent bonds. Hence, valency of carbon is 4
b) The valency of fluorine is seven. This means that the outer electron shell of a fluorine atom contains seven electrons.
c) The valency of a metal is the number of its valence electrons. Thus the valency of calcium is 2 since it has 2 valence electrons. 2. If in the valence shell, the number of electrons is > 3, the atom is of a non metal
d) To determine the valency of the ionic molecule phosphorus tetraoxide (PO4, four atoms of oxygen and one atom phosphorus) you should multiply the total valency of the four oxygen atoms (valency 2) and subtract that from the valency of the phosphorus atom (valency 5), That reveals the valency of (PO4) is 3.
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